Linear Algebra Examples

x + 3 y = - 6

$x + 3 y = - 6$

Step 1

Subtract

$x$ from both sides of the equation.

$3 y = - 6 - x$

Step 2

Divide each term in

$3 y = - 6 - x$ by

$3$ and simplify.

Tap for more steps...

Step 2.1

Divide each term in

$3 y = - 6 - x$ by

$3$ .

$\frac{3 y}{3} = \frac{- 6}{3} + \frac{- x}{3}$

Step 2.2

Simplify the left side.

Tap for more steps...

Step 2.2.1

Cancel the common factor of

$3$ .

Tap for more steps...

Step 2.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 6}{3} + \frac{- x}{3}$

Step 2.2.1.2

Divide

$y$ by

$1$ .

$y = \frac{- 6}{3} + \frac{- x}{3}$

Step 2.3

Simplify the right side.

Tap for more steps...

Step 2.3.1

Simplify each term.

Tap for more steps...

Step 2.3.1.1

Divide

$- 6$ by

$3$ .

$y = - 2 + \frac{- x}{3}$

Step 2.3.1.2

Move the negative in front of the fraction.

$y = - 2 - \frac{x}{3}$

Step 3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 4